- #1
dwn
- 165
- 2
Homework Statement
Attached image
Using node analysis:
ix(0-) = (v-4)/10 + v/3 + v/5 = 0
v = 0.632
ix(0-) = -v/3 = -0.211 A
I don't understand why they didn't use a current divider since there is a 5 ohm resistor in parallel with the 3 ohm. Current changes for resistors that are in parallel...
il(0-) = v/5 = -0.63/5 = 0.126A
Then when it comes to solve for v(0+) = di/dt = d(0.126)/dt = 0
How can the voltage across an inductor be zero when it's charged by the 4V source for t < 0??