I am given a RLC circuit with a AC power source (e.g. signal generator), and i want to find the reactance of the capacitor.
Given: R = 2200 Ohms, L = .025 H, C = (1 x 10-9) F, V0 = 5 V
f = 3000 Hz
edit: Sorry i wrote wrong formula.. here is the correct one:
Reactance of Capacitor = 1 / ω C
The Attempt at a Solution
I know how to solve this problem, but i am not sure what value to use for ω.
My teacher refers to ω as the "frequency", but isn't it supposed to be ω = 2 pi f ?
So, simply put, am i supposed to use the 3000 Hz as my ω, or do i use 2 pi f as my ω?