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RLC circuit problem

  1. Jun 18, 2017 #1
    1. The problem statement, all variables and given/known data

    http://imgur.com/a/3xSYb
    [​IMG]

    2. Relevant equations
    RLC equations:

    q= Qmax e ^ -Rt/2L cos wd t

    wd = [ 1/LC - (R/2L)^2] ^ 1/2

    3. The attempt at a solution
    So, im trying using Kirchoff law, but not sure what the question asks.



    I thought it may be a trick and after a long long time C will be fully charged and L will act as a simple wire, so it will be a simple circuit with Resistors.
     
    Last edited: Jun 18, 2017
  2. jcsd
  3. Jun 18, 2017 #2
    I canot see the image attached.
     
  4. Jun 18, 2017 #3
    I added a imgur link. Can you open it now?
     
  5. Jun 18, 2017 #4

    phinds

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    Gold Member
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    Your image isn't showing up for me either and I see no link. Your best bet is to embed the image here directly, not with a link.
     
  6. Jun 18, 2017 #5
    I don't know.
    For me, there's a link and shows the image. Don't know how it's not showing.
     
  7. Jun 18, 2017 #6

    gneill

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    Staff: Mentor

    Yes, the phrase "after a sufficiently long time" is a typical hint used in problems to refer to the eventual steady state conditions. Suppress the reactive components as you suggest and analyze the resulting resistor network.

    It is always better to load your images to our server here so that helpers do not have to follow off-site links to see your problem.

    Off-site links have a tendency to get broken over time, or have their content removed, making their threads less than useful to future members seeking information.
     
  8. Jun 18, 2017 #7
    Thank you.

    Im in doubt should i remove the C and keep it as a RL circuit or both of them.


    Sorry my bad. I will add them properly
     
  9. Jun 18, 2017 #8

    gneill

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    Staff: Mentor

    Open (remove) the C and short the L.
     
  10. Jun 18, 2017 #9

    SammyS

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    1ssnmTl.jpg
     
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