Question and part 1 as above. The second part involves solving this equation where [tex]L = 8R^2 C[/tex]. The system is kept in steady state by maintaining V(t) = -Q/C (constant). V(t) is then set to 0 at t=0.
It also says "Note that V(t)=0 for t>0 and that appropriate initial conditions
at (or just after) t=0 are that q=Q and dq/dt= −Q/CR."
The Attempt at a Solution
The first part is just very tedious math, but I managed to get it.
The second part is just a second order ODE, but I am unable to get the answer which is
Given the differential equation above, and substituting V = -Q/C, dV/dt = 0, the right hand side becomes a constant. This means that there is a particular integral (q = k = Q), but the answer does not have the form q = Q +... !
I did it a few times but keep getting back to the same problem. However, if I do attempt a solution that omits the particular integral, I do get the answer needed. Why is this the case?