- Find the desired currents and voltages for the circuit below.
These are my attempts at doing this question, and I was wondering if I am correct so far.
At t= 0-, i(L) will be 0A, since the capacitor acts as a open circuit.
However, I'm not sure why V(c) at t=0- will be -20V as given by the answers. Won't it be 0V?
Moving on, since current in inductor and voltage in capacitor does not change immediately, the values for t=0+ will be the same as t=0-. (Again, I'm not sure why it is -20V for the capacitor, could someone explain to me?)
I'm not sure how to proceed, but if it was me, I will probably transform the circuit? to:
Taking KVL on the left loop,
-80+20i1+ Vc+20=0 --(1)
Taking KVL on right loop,
-20-Vc+40iL+1/L (integerate voltage) -- (2)
I also know Vc = 1/C (integerate i1-iL)
Now the thing is am I making this more complicated than I should? or is this correct so far?