- #1

KUphysstudent

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## Homework Statement

Calculate the rms speed of one nitrogen molecule at 27 Celcius

## Homework Equations

sqrt(v^2) = sqrt((3kT)/(m))

## The Attempt at a Solution

sqrt(v^2) = sqrt((3kT)/(m))

k = 8.62*10^-5 eV/K

T = 300 K

3kT = 0.078 eV

m = 14 g/mol

m = 0.014 kg/mol

3kT/m = 0.078 eV/0.014 kg/mol = 5.571

if 5.571 was 557.1 m/s I would assume it was correct but I doing something completely wrong here, any help will be appreciated. edit nevermind that statement since I have to take the sqaure root also

sqrt(5.571)

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