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I am trying to prove [tex]\frac{tanx+1}{tanx-1}=\frac{secx+cscx}{secx-cscx}[/tex]

I am working on the right side and trying to get it to the same form as the left side.

I get to [tex]\frac{1+2sinxcosx}{sin^{2}x-cos^{2}x}[/tex] which I COULD apply the fact that sin2x=2sinxcosx as well as cos^2x-sin^2x=cos2x (after multiplying both top and bottom by -1) but that gets me to

[tex]\frac{-Sin(2x)-1}{cos(2x)}[/tex] which looks completely useless!

Anyone see something I don't? Just point me in the right direction :) Thanks again

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# Roadblock in trig identity

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