Hi,(adsbygoogle = window.adsbygoogle || []).push({});

I am trying to prove [tex]\frac{tanx+1}{tanx-1}=\frac{secx+cscx}{secx-cscx}[/tex]

I am working on the right side and trying to get it to the same form as the left side.

I get to [tex]\frac{1+2sinxcosx}{sin^{2}x-cos^{2}x}[/tex] which I COULD apply the fact that sin2x=2sinxcosx as well as cos^2x-sin^2x=cos2x (after multiplying both top and bottom by -1) but that gets me to

[tex]\frac{-Sin(2x)-1}{cos(2x)}[/tex] which looks completely useless!

Anyone see something I don't? Just point me in the right direction :) Thanks again

**Physics Forums | Science Articles, Homework Help, Discussion**

Dismiss Notice

Join Physics Forums Today!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# Homework Help: Roadblock in trig identity

**Physics Forums | Science Articles, Homework Help, Discussion**