A rocket, initially at rest on the ground, accelerates straight upward from rest with constant acceleration 53.9 . The acceleration period lasts for time 5.00 until the fuel is exhausted. After that, the rocket is in free fall.
Find the maximum height reached by the rocket. Ignore air resistance and assume a constant acceleration due to gravity equal to 9.8 .
Distance = 1/2 at^2
Velocity = u + at
The Attempt at a Solution
So far what I get
distance = 1/2 x 53.9 x 5^2 = 673.75 m
V = 0 + 53.9 x 5 = 269.5 m/s
and from there I seem to be stuck. I dont know what else to do, if there is someone to help guide me or of this ditch I'd appreciate it.