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Number 2 is a=((Vrk)/(1-kt))-g.

I think that since there is no gravity in free space the answer is a=((Vrk)/(1-kt)). Is this correct and is my reason for it correct?

- Thread starter mopar969
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Number 2 is a=((Vrk)/(1-kt))-g.

I think that since there is no gravity in free space the answer is a=((Vrk)/(1-kt)). Is this correct and is my reason for it correct?

- #2

Delphi51

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There IS gravity in space. It is the gravitational force that holds the moon in orbit around the Earth.

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Maybe.

Could you explain the formula and what the various terms represent?

Could you explain the formula and what the various terms represent?

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Delphi51

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The acceleration of a rocket fired vertically upward is a = (-Vr/m)(dm/dt)-g. Suppose the rate of ejection mass by a rocket is a constant (dm/dt)=-km(initial) therefore, m=m(initial)(1-kt). Therefore under the conditions of the previous equation a = ((Vrk)/(1-kt))-g. Now, in free space, what would the answer to the last equation be?

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Delphi51

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