- #1

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What is the speed V(gas) of the exhaust gas relative to the rocket?

- Thread starter ElectricMile
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- #1

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What is the speed V(gas) of the exhaust gas relative to the rocket?

- #2

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can anyone help me out?

- #3

Tide

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Does this equation look familiar to you?

[tex]v = v_e \ln \frac {M_0}{M}[/tex]

[tex]v = v_e \ln \frac {M_0}{M}[/tex]

- #4

HallsofIvy

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By conservation of momentum, we must have

(159/160)M(v+15.3)- (1/160)MV= Mv. I don't see any way of solving for V without knowing v (just as Tide's equation required v

- #5

Clausius2

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Hey Hallsofivy! Now I've noticed you don't ask the famous adage "What have you done till now?" and "show me what you've done!".HallsofIvy said:^{2}for 1 sec. , it gained 15.3 m/s: it's final speed is v+15.3 and it's final momentum is (159/160)M(v+15.3). The expelled gas has mass (1/160)M and, with velocity -V (opposite to the direction of the rocket) so its momentum is -(1/160)MV.

By conservation of momentum, we must have

(159/160)M(v+15.3)- (1/160)MV= Mv. I don't see any way of solving for V without knowing v (just as Tide's equation required v_{e}).

Times are changing....(nostalgia... )

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