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Rocket in space

  1. Oct 18, 2004 #1
    A rocket is fired in deep space, where gravity is negligible. In the first second it ejects (1/160) of its mass as exhaust gas and has an acceleration of 15.3 m/s^2.

    What is the speed V(gas) of the exhaust gas relative to the rocket?
     
  2. jcsd
  3. Oct 18, 2004 #2
    can anyone help me out?
     
  4. Oct 18, 2004 #3

    Tide

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    Does this equation look familiar to you?

    [tex]v = v_e \ln \frac {M_0}{M}[/tex]
     
  5. Oct 19, 2004 #4

    HallsofIvy

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    More fundamentally, use conservation of momentum. Take the initial values of the mass and speed of the rocket to be M and v. The initial momentum is Mv. After ejecting (1/160)M, the rocket's mass is (159/160) M. Since it accelerated at 15.3 m/s2 for 1 sec. , it gained 15.3 m/s: it's final speed is v+15.3 and it's final momentum is (159/160)M(v+15.3). The expelled gas has mass (1/160)M and, with velocity -V (opposite to the direction of the rocket) so its momentum is -(1/160)MV.

    By conservation of momentum, we must have
    (159/160)M(v+15.3)- (1/160)MV= Mv. I don't see any way of solving for V without knowing v (just as Tide's equation required ve).
     
  6. Oct 19, 2004 #5

    Clausius2

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    Hey Hallsofivy! Now I've noticed you don't ask the famous adage "What have you done till now?" and "show me what you've done!".

    Times are changing....(nostalgia... :frown: )
     
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