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Calculate the maximum height H of point A above the earth's surface at which the rocket will momentarily come to rest, before it starts falling back on the earth.

So I know energy (kinetic and potential) is conserved? I've tried using E(initial) = E(final) --> (1/2)mv0^2 = mgh, but figured this wouldn't work because g is not 9.8 m/s^2 far from the earth. Instead, I used (1/2)mv0^2 - (GMm)/Re = -(GMm)/H. I solved for H, but it did not give me the correct solution, which is 4.08 x 10^6. Can anyone help me out?