(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

You are working as an engineer in a space company. During launches, rockets often discard unneeded parts. A certain rocket starts from rest on the launch pad and accelerates upward at a steady 3.30m/s^{2}. When it is 235m above the launch pad, it discards a used fuel canister by simply disconnecting it. Once it is disconnected, the only force acting on the canister is gravity. You can ignore air resistance. How high is the rocket when the canister hits the launching pad, assuming that the rocket does not change its acceleration?

[The back of book Answer is: 945m]

2. Relevant equations

V^{x}=V_{0x}+a_{x}t

x=x_{0}+V_{0x}t+1/2 a_{x}t^{2}

V_{x}^{2}=V_{0x}^{2}+2a_{x}(x-x_{0})

3. The attempt at a solution

235=0+0+1/2 (3.30)t^{2}

235=1.65t^{2}

t^{2}=235/1.65

t=11.93s

V_{x}=0+9.8(11.93)

V_{x}=116.96m/s

116.96^{2}=0^{2}+2(9.8)(x-235)

116.96^{2}=2(9.8)(x-235)

116.96^{2}/2(9.8)=x-235

116.96^{2}/2(9.8) + 235 = x

x=932.94m

I don't know to get 945m =( .. I would appreciate it if someone can solve this problem and show the steps correctly..

Thank you so much in advance

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# Homework Help: Rocket Launching

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