A rocket is accelerating upwards from rest in a uniform gravitational field g. Notation: m(t) is the mass of the rocket plus remaining fuel, m0 is the initial total mass, vex is the exhaust speed (relative to the rocket), and k is the rate, in kg/s, at which fuel is consumed. By considering momentum changes in a short time dt, show that mdv/dt = kv(ext) - mg(upward direction is positive). Assuming k is constant, find the speed v as a function of the remaining mass m. Show that, if k is very large, it agrees with the result derived in class (without gravity). Ok, so i have already proved the first part. P(t)=mv and P(t+dt) = (m+dm)(v+dv)-dM(v-v(ext)) =mv+vdm+dmv(ext) The a couple of steps later we get: -mgdt=mdv+(ext)(dm/dt) so we get -mg=mdv/dt -kv(ext), where -k=dm/dt and therefore mdv/dt=kv(ext) - mg. Ok, so I'm a little stuck on the second part. Not really sure where to start off. Any hints?