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Rocket propulsion

  1. Nov 2, 2007 #1
    Rocket propulsion

    In the serway textbook at the rocket propulsion section it is mentioned that
    If the fuel is ejected with a speed v_e relative to the rocket (the subscript e stands for exhaust, and v_e is usually called the exhaust speed), the velocity of the fuel relative to the Earth is v-v_e.

    May I know why the velocity of the fuel relative to the Earth is v-v_e?
  2. jcsd
  3. Nov 2, 2007 #2


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    Staff: Mentor

    Velocity is a vector and the velocity (v) of the rocket points away from earth and is measured with respect to earth. v_e is measured with respect to the rocket and is in the opposite direction of travel. The velocity of the exhaust has a forward velocity v to which one adds -v_e to get the velocity with respect to earth.

    It's like a person on a train, with the velocity v, who throws an object at velocity v_o. If v_o is forward with the train, the combined velocity (as would be observed by someone standing on a platform) is v + v_o. If the v_o is oriented to toward the rear (opposite v), then the combined velocity is v - v_o.

    This also of a person in a boat traveling with v with respect to water, or a plane in the air with an air speed v. The effective velocity with respect to land (shore line or ground) is v +/- v_fluid, where v_fluid is the stream or air velocity. Here I use a simple example of parallel motion. It's a little more complicated -



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