# Homework Help: Rocket's Initial Mass

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1. May 3, 2017

### Dopplershift

The problem states:
Typical chemical fuels yield exhaust speeds of the order of 103 m/s. Let us imagine we had a fuel that gives v0 = 3 × 105 m/s. What initial mass of fuel would the rocket need in order to attain a final velocity of 0.1c for a final mass of 1 ton?

I derived the equation in the first part of the problem:

v - v_0 = v_e \ln(\frac{m_0}{m})

Solving for the initial mass, m, yields

m_0 = me^{\frac{\Delta v}{v_e)}}

I plug in that.

0.1c = 3.0*10^7
v0 = 3.0*10^5
vee = 1.0*10^3
v - v0 = 3.0 *10^7 - 3.0*10^5 = 2.97*10^7
m = 1000 kg
I plug in these numbers and I am getting infinity. What am I doing wrong?

Thanks!

2. May 3, 2017

### Staff: Mentor

The initial velocity should be 0, not 3*105 m/s.

3*105 m/s is the exhaust velocity of the hypothetical fuel, the number for chemical rockets is just given as comparison. The number will be very large, but you should't get infinity anywhere.

Please work with units, that makes it easier (especially for you) to spot mistakes.

3. May 3, 2017

### Dopplershift

I'm confused, how is the initial velocity zero? It says that the fuel gives us a v0 of 3.0*105?

The problem is when I plug in the values of the conditions into my final equation, (equation 2).

4. May 3, 2017

### scottdave

Based on your formulas, m0 calculates to (1000 kg)*e^29700, which is approx 3.5 x 10^12901 (not infinity), but too large for your calculator.

5. May 3, 2017

Thank you!

6. May 3, 2017

### haruspex

If that v0 is the initial speed of the rocket then the question makes no sense. How can the fuel give it that initial speed, before any fuel is burnt? I believe v0 is the exhaust speed, and the question is saying that although a typical exhaust speed is only 1000m/s, just suppose we had one with an exhaust speed 300 times as great.

7. May 3, 2017

### Staff: Mentor

That is how I interpreted the question as well.

8. May 4, 2017

### scottdave

In perspective, the mass of the Earth is 5.97 x 10^24 kg.

9. Jan 8, 2018

### Ray Vickson

Your use of $v_0$ is inconsistent: in the rocket equation, $v_0=$ initial speed of the rocket, That is $v_0 = 0$ nowhere near $3 \times 10^5$ (m/s). The "speed" $3 \times 10^5$ (m/s) is the speed of the exhaust gas relative to the rocket body.

One final quibble: the rocket equation as you wrote it is for non-relativistic rockets, using classical mechanics and Newton's equations of motion. The final speed $0.1 c$ sought in this problem is getting a bit into territory where relativity matters, so in pirnciple one ought to use a relativistic version of the rocket eqution. Of course, it will make very little difference in this particular problem---but it is always a good idea to know what kinds of approximations you are using.

10. Jan 8, 2018

### Staff: Mentor

This problem is from May, it is unlikely that someone is still working on it.

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