Hi. My question is this. A uniform rod of length 2L is held resting on a horizonal table with length L+a projecting over the edge. If the support is removed, show tthat the rod willb egin to slide over hte ege when it has turned through an angle tan^-1(mu*L^2/(L^2+ 9a^2)). mu is the coeffiecent of static friction. I am having trouble finding the equation of motion to start this problem. m*a=mgsin(theta)-mu*m*g*cos(theta) I think is the right way to start since force of friction=mu*m*g*cos(theta). Now how do I go from here to get the angle it slips off? And what should the angle of rotation be?