1. The problem statement, all variables and given/known data A thin rod of mass m = 1 kg and length l=1m is placed along the hypotenuse side of a wedge lying on a frictionless floor having mass M =5kg and angle 60° . At t= 0 the system is released from rest. Both the objects are free to move .Find the speed of the wedge when the rod makes an angle 30° with the floor. 2. Relevant equations 3. The attempt at a solution Let V be the speed of the wedge and v be the speed of the CM of the rod . Applying conservation of momentum MV = mvx Applying energy conservation (mgl/2)(sin60° – sin30°) = (1/2)MV2+ (1/2)mv2+ (1/2)Iω2 Not sure how to proceed. I guess we need to find some constraint relation . I would be grateful if somebody could help me with the problem.