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Role of integration factor

  1. May 30, 2009 #1
    [tex]
    \frac{dp}{dt}+2tp=p+4t-2
    [/tex]
    [tex]
    e^{\int (2t-1)dt}=e^{t^2 -t}
    [/tex]
    then we do

    [tex]
    \frac{d}{dt}[e^{t^2 -t}]=...
    [/tex]
    why??
    i was told that i will get the original left side of the equation times p.
    i didnt get the same result


    what is the role of integration factor
    ??
     
  2. jcsd
  3. May 30, 2009 #2

    Cyosis

    User Avatar
    Homework Helper

    An integrating factor is a function with which you multiply the differential equation to help facilitate the solving of the differential equation.

    There was a similar question here a few days ago, where I did part of the calculation.

    https://www.physicsforums.com/showthread.php?t=316907

    Check post 4.
     
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