 #1
Undeterred247
 6
 4
 Homework Statement:
 A very small steel marble is shown rolling at a constant speed on a horizontal table. The marble leaves the table at M, falls, and hits the ground at N. This is illustrated in the diagram below which is drawn to scale. Calculate the time it took the marble to travel from L to N.
 Relevant Equations:

p(t) = p0 +v0 * t +1/2*a*t^2
a = g = 9.81m/s^2 = 981cm/s^2
Vertical position (x component):
y(t) = y0 +v0 * t 1/2*g*t^2
Position yx(t) = 0cm = 40cm + 0 *t 1/2 * 981cm/s/s * t^2
edit: I replaced v0 = 0 and got t = 0.286s, which is incorrect according to the submission.
This didn't work so I thought maybe by finding the angle of the throw would help with the following equation but there are still not enough parts to it:
yx(t) = y0 +v0 * sintheta * t 1/2 *g * t^2
yx(t) = 40cm + v0 * sin(36.84) * t 1/2 *981cm/s/s *t^2
Theta = angle of throw where
horizontal = 30cm
vertical = 40cm
hypotenuse = 50cm
I found https://www.physicsforums.com/threads/rollingmarbleontable.469634/ which is similar to this problem but I still don't understand how to solve this. Please help!
y(t) = y0 +v0 * t 1/2*g*t^2
Position yx(t) = 0cm = 40cm + 0 *t 1/2 * 981cm/s/s * t^2
edit: I replaced v0 = 0 and got t = 0.286s, which is incorrect according to the submission.
This didn't work so I thought maybe by finding the angle of the throw would help with the following equation but there are still not enough parts to it:
yx(t) = y0 +v0 * sintheta * t 1/2 *g * t^2
yx(t) = 40cm + v0 * sin(36.84) * t 1/2 *981cm/s/s *t^2
Theta = angle of throw where
horizontal = 30cm
vertical = 40cm
hypotenuse = 50cm
I found https://www.physicsforums.com/threads/rollingmarbleontable.469634/ which is similar to this problem but I still don't understand how to solve this. Please help!
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