Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Roll resistance calculation

  1. May 6, 2009 #1
    Hi to all

    Please help me to clarify this situation:

    There is a rotated wheel on a plan surface. What torque/power will be necessary to spring an obstacle with a concrete height.

    For ex. here are some data:

    1.Wheel mass 10 kg
    2.Wheel radius 0,3 m
    3.Rotation speed 100 RPM
    4.Obstacle height 0,01 m

    Which formulas must I use to determine torque/power to get the wheel rotating at that speed without obstacle, and how much must be increased these parameters to pass obstacle without slowly speed.

    Here is an image, hope it will help to understand what I mean.

    Thanks
     

    Attached Files:

  2. jcsd
  3. May 6, 2009 #2

    tiny-tim

    User Avatar
    Science Advisor
    Homework Helper

    Welcome to PF!

    Hi vladim1! Welcome to PF! :smile:

    Isn't this just an energy problem?

    As son as the roller hits the obstacle, it will start rotating about the obstacle instead of about its centre … you have to find what energy it needs to just reach "vertical". :wink:
     
  4. May 7, 2009 #3
    Ok, how you say then I must calculate energy whith formula E=mgh, to determine what power I need to pass an obstacle with "h" height.

    But, how is explained that a wheel with bigger radius pass a same obstacle easier than one with smaller?

    How much role play differences in dimentions, is there something with balance.
     
  5. May 7, 2009 #4

    tiny-tim

    User Avatar
    Science Advisor
    Homework Helper

    uh-uh, you tell me :wink:

    for a wheel of density ρ, radius r, and speed v, what is its energy, and so what is the maximum height h of an obstacle that it will clear?

    and how does that h depend, dimensionally, on ρ, r, and v, separately? :smile:
     
  6. May 7, 2009 #5
    Thinking we discuss about thing I dont need.

    Me interest is to calculate rolling resistance (in N) for a surface which have obstacles of 1cm height (eg. after each 5cm). Also I observe that a heighter wheel go easier after road's deformations.
     
  7. May 11, 2009 #6
    I found a formula to calculate force needed to aply on axle (pushed wheel) to overcome obstacle:

    F=m*g*sqrt(2rh-h^2)/(r-h)

    where:

    m= load
    r= radius of wheel
    h= obstacle height

    Which formula must I use to calculate torque needed to overcome same obstacle, rotation start from rest wheel.

    Can I use T=F*r ?

    F - force calculated with above formula
    r - wheel radius.
     
  8. May 13, 2009 #7
    T = F*(r-h)

    To derive the formula that you found, simply take the sum of the moments about the tip of the obstacle.

    sum of Moments: F*(r-h) - mg*sqrt[r^2 - (r-h)^2] = 0
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook




Similar Discussions: Roll resistance calculation
Loading...