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The lift hill is 18 m highabd it goes up the lift hill at 2.50 m/s

The second hill is 5.5m high.

Wants to know the speed at the top of the second hill.

do i really care about the weight of the car?

This is what i have so far

PEtop1 +KEtop1 = KE bott

2*9.80*18 +2.5^2 = v^2 bott

V bott = 18.9 m/s

second formula was

Ke bott - Pe top1 = KE top 2

18.9^2 - 2*9.80*5.5 = V^2 top 2

Vtop 2 = 15.9 m/s and that is my final answer is that look right

thanks