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f(x)=sin2piex [-1,1]

i found the derivative cos 2pie x, but what do i do, and what does the theorem mean when f is differentiable on the open interval (a,b)

- Thread starter afcwestwarrior
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- #1

- 457

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f(x)=sin2piex [-1,1]

i found the derivative cos 2pie x, but what do i do, and what does the theorem mean when f is differentiable on the open interval (a,b)

- #2

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what do i do

- #3

HallsofIvy

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You are also asked to "find all the numbers c that satisfy the conclusion of rolle's theorem." Okay, what is the conclusion of Rolle's theorem?

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well all these are true, so how do u find all numbers c

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[itex]f'(c)=0[/itex]well all these are true, so how do u find all numbers c

10 chars....

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HallsofIvy

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Again, what **is** the conclusion of Rolle's theorem?

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Gib Z

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No The derivative of [itex] \sin (2\pi x ) [/itex] is not that. Using the chain rule it is [itex]2\pi \cos (2\pi x)[/itex]

f(x)=sin2piex [-1,1]

i found the derivative cos 2pie x, but what do i do, and what does the theorem mean when f is differentiable on the open interval (a,b)

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