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tmilla
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Homework Statement
Two bicycle tires are set rolling with the same initial speed of 3.60 m/s along a long, straight road, and the distance each travels before its speed is reduced by half is measured. One tire is inflated to a pressure of 40 psi and goes 18.7m ; the other is at 105 psi and goes 93.3m . Assume that the net horizontal force is due to rolling friction only.
What is the coefficient of rolling friction for the tire under low pressure?
Homework Equations
Vf^2=Vi^2 +2ax
Ur=a/g ?? (Ur= coefficient of rolling friction
The Attempt at a Solution
1st Tire:
-(3.60)^2/(2*18.7) = a = -.3465
.3465/9.81=Ur
This is wrong, but I honestly have no idea what to do. Help is GREATLY appreciated! :)