A ring of mass 2.4kg, inner radius 6c.0cm, and outer radius 8.0cm is rolling (without slipping) up an inclined plane that makes an angle of theta=36.9 with the horizontal. At the moment the ring is x=2.0 m up the plane its speed is 2.8 m/s. the ring continues up the plane for some additonal distance and then rolls abck down. Assuming that the plane is long enough so that the ring does not roll off the top end, how far up the plane does it go?(adsbygoogle = window.adsbygoogle || []).push({});

help by one of you good samaritans would be greatly appreciated.

so far, ive gotten :

I=.5MR1^2+.5MR2^2

I=.5(2.4)(.06^2)+.5(2.4)(.08)^2

I= .012 kg M^2

what do i do next? i am unaware of how to find distance and incorporate theta into this problem

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# Homework Help: Rolling motion of a rigid body

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