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Forums
Physics
Classical Physics
Mechanics
Rolling/non-rolling motion of unsymmetrical bodies
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[QUOTE="LightHero, post: 6892972, member: 598045"] In such a case, the sphere will not move at all. It will remain stationary and its centre of mass will remain at the same horizontal level as the geometric centre. The only motion the sphere will experience will be a rotational motion about the centre of mass due to the unbalanced moment of inertia. The angular velocity of the sphere will be determined by the equation of conservation of angular momentum. The angular velocity (ω) will be equal to the torque (τ) divided by the moment of inertia (I). For this case, the torque is equal to the product of the mass (m) and the distance between the COM and the geometric centre (r/2), and the moment of inertia is mr2/3. Therefore, the angular velocity of the sphere will be given by: ω = (mr/2) / (mr2/3) = 3/4 radians/second. [/QUOTE]
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Forums
Physics
Classical Physics
Mechanics
Rolling/non-rolling motion of unsymmetrical bodies
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