- #1
skepticwulf
- 74
- 1
According to KMT, Avarage kinetic energy of 1 mole gas is=(3/2) x R x T
So , in winter in my cold room ,
the gases have Kea=34J/mole (T=5oC)
and in summer that figure climbs to, -roughly- 37J/mole, (T=25oC)
Difference is , 3J per mole.
If my rooms dimensions are 3m x 3m x 4m, volume is 36m^3, so
n is = PV/RT=(1)(36.000)/(0.082)(15+273) (avg temp of 15oC taken to compute number of moles)
n=1524 mole ==> 3J x 1524= 4573J That's the difference of Energy between winter and summer for my room.
So, does that mean the air molecules in my room carries 4573J more energy in summer compared to winter?
How can I put time factor? Can I say they carry that per second?
Power=E/t=4573/1=4573 Watts??
Can I assume they hit my body constantly it's as if 4573W heater is in the room and warms me up??
So , in winter in my cold room ,
the gases have Kea=34J/mole (T=5oC)
and in summer that figure climbs to, -roughly- 37J/mole, (T=25oC)
Difference is , 3J per mole.
If my rooms dimensions are 3m x 3m x 4m, volume is 36m^3, so
n is = PV/RT=(1)(36.000)/(0.082)(15+273) (avg temp of 15oC taken to compute number of moles)
n=1524 mole ==> 3J x 1524= 4573J That's the difference of Energy between winter and summer for my room.
So, does that mean the air molecules in my room carries 4573J more energy in summer compared to winter?
How can I put time factor? Can I say they carry that per second?
Power=E/t=4573/1=4573 Watts??
Can I assume they hit my body constantly it's as if 4573W heater is in the room and warms me up??