- #1

bill nye scienceguy!

- 127

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thanks

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- Thread starter bill nye scienceguy!
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- #1

bill nye scienceguy!

- 127

- 0

thanks

- #2

rbj

- 2,227

- 9

this thing sounds like what happens with a Moog 4-pole Low Pass Filter. once you surround it with a loop and gain, you just solve the new transfer function for the poles and you can see that they move outward from the original place like 4 corners of a square centered at the original location. are you going to make me do the math to show you?

- #3

bill nye scienceguy!

- 127

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anyway, do you mean that the open loop transfer function G(s)=1/(s+2)^4 would become something like Gc(s)=K/[(s+2)^4+K]?

I still can't really visualise what the locus would look like though. Does it just expand outwards from s=-2, following the four asymptotes?

- #4

rbj

- 2,227

- 9

anyway, do you mean that the open loop transfer function G(s)=1/(s+2)^4 would become something like Gc(s)=K/[(s+2)^4+K]?

I still can't really visualise what the locus would look like though. Does it just expand outwards from s=-2, following the four asymptotes?

yes it does. but it's not really asymptotes. the loci of the roots really are the four corners of a square centered at

[tex] G_c(s) = \frac{K G(s)}{1 \ + \ K G(s)} = \frac{K}{1/G(s) \ + \ K} [/tex]

now, to find the poles of

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