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calculate the RMS (root mean square) of this function.

the period T=4

the formula is

[tex]V_{rms}=\sqrt{\frac{1}{T}\int_{0}^{T}V_r^2dt}[/tex]

[tex]V_{rms}=\frac{1}{4}4\int_{0}^{T}(4t)^2dt}[/tex]

[tex]V_rms=\sqrt{s}=\sqrt{\frac{16}{3}}[/tex]

the solution says that they divide the graph into 4 traingles

and they sum their areas

but they dont use the integral?

why they say (4t)^2

from where the 4t comes from?

why they say that its the root of the area

why they dont divide by the period?

the period T=4

the formula is

[tex]V_{rms}=\sqrt{\frac{1}{T}\int_{0}^{T}V_r^2dt}[/tex]

[tex]V_{rms}=\frac{1}{4}4\int_{0}^{T}(4t)^2dt}[/tex]

[tex]V_rms=\sqrt{s}=\sqrt{\frac{16}{3}}[/tex]

the solution says that they divide the graph into 4 traingles

and they sum their areas

but they dont use the integral?

why they say (4t)^2

from where the 4t comes from?

why they say that its the root of the area

why they dont divide by the period?

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