So there's this ODE:(adsbygoogle = window.adsbygoogle || []).push({});

yy''-(y')^{2}= y^{3}

After doing some work it gets to this point:

(y')^{2}=2y^{3}

Taking the root:

y' = +-(2y^{3})^{1/2}

My question is, what do I do with the +-?

Do I solve 2 different integrals? Assume that this is positive?

Does it matter if it has starting conditions (y(x)=a, y'(x)=b)?

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# Roots of a derivative

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