- #1

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## Main Question or Discussion Point

So there's this ODE:

yy''-(y')

After doing some work it gets to this point:

(y')

Taking the root:

y' = +-(2y

My question is, what do I do with the +-?

Do I solve 2 different integrals? Assume that this is positive?

Does it matter if it has starting conditions (y(x)=a, y'(x)=b)?

yy''-(y')

^{2}= y^{3}After doing some work it gets to this point:

(y')

^{2}=2y^{3}Taking the root:

y' = +-(2y

^{3})^{1/2}My question is, what do I do with the +-?

Do I solve 2 different integrals? Assume that this is positive?

Does it matter if it has starting conditions (y(x)=a, y'(x)=b)?