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Mathematics
General Math
Roots of a Polynomial Function A²+B²+18C>0
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[QUOTE="Opalg, post: 6779130, member: 703375"] [sp]Good point – I completely overlooked that. However, if one or three of the roots are negative then $C$ will be positive, so the inequality $A^2+B^2+18C>0$ will certainly hold. So the remaining case to deal with is if two of the roots are negative and the third one is positive. I'll have to think about that ... . [/sp] [B]Edit:[/B] [sp]The polynomial $x^3 + x^2 - x - 1 = (x+1)^2(x-1)$ has $A=1$, $B=C=-1$, and $A^2 + B^2 + 18C = -16 <0$. So I think that the problem probably needed an extra condition to exclude the case where two of the roots are negative. [/sp] [/QUOTE]
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Roots of a Polynomial Function A²+B²+18C>0
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