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Roots of a polynomial

  1. May 16, 2008 #1
    [SOLVED] roots of a polynomial

    1. The problem statement, all variables and given/known data
    Let P(x) be a polynomial of odd degree with real coefficients. Show that the equation P(P(x))=0 has at least as many real roots as the equation P(x) = 0, counted without multiplicities.


    2. Relevant equations
    By the FTC, P(x) and P(P(x)) factor into complex linear factors.


    3. The attempt at a solution
    Please just give me hint.

    By the odd degree, we know that both P(x) and P(P(x)) have at least one real root.

    By the FTC, P(x) and P(P(x)) factor into complex linear factors.

    Oh wait, let \alpha_1,...,\alpha_m be the roots of P(x)=0. Because P(x) has odd degree, we know that p(R) = R. So, we can find distinct \beta_1,...,\beta_n such that P(\beta_i) = \alpha_i. That was easy. I guess I will post it anyway.
     
  2. jcsd
  3. May 16, 2008 #2

    cristo

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    :uhh:
     
  4. May 16, 2008 #3
    OK fine delete it.
     
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