By pythagorean identity, ##\sin(x)^2 + \cos(x)^2 = 1##, so ##\sin(x) = \sqrt{1 - \cos(x)^2}##; also, ##\sinh(x)^2 - \cosh(x)^2 = - 1##, therefore ##\sinh(x) = \sqrt{\cosh(x)^2 - 1}##.(adsbygoogle = window.adsbygoogle || []).push({});

Happens that the last equation is incorrect, here is a full list of the correct forms for the hyperbolics:

https://de.wikipedia.org/wiki/Hyperbelfunktion#Umrechnungstabelle and here is a full trigonometric list for comparation: https://es.wikipedia.org/wiki/Identidades_trigonométricas#Relaciones_b.C3.A1sicas.

So, why the 'normal' trigonometrics no needs of completary functions, like Abs and Sgn, and the hyperbolic trigonometrics needs in some case?

**Physics Forums - The Fusion of Science and Community**

# Roots, signs and abs

Have something to add?

- Similar discussions for: Roots, signs and abs

Loading...

**Physics Forums - The Fusion of Science and Community**