A rope is wound around a cylinder of mass 4kg and with moment of inertia I=0.020 kg.m^2 about an axis along the cylinder axis, see attachment. If the cylinder rolls without slipping, (a)what is the linear acceleration of its mass center? (b)Repeat for the case where no friction force exists between the table and the cylinder.(adsbygoogle = window.adsbygoogle || []).push({});

So we have a force of 20N applied in the direction shown in the attachment, and the radius of the cylinder is r=10cm.

My attempt: (a)torque T=I*(alpha) where (alpha) is angular acceleration, therefore (alpha)=T/I = 20*.1/.02 = 100rad/s^2

a_tangential=r*(alpha) = 10m/s^2.

a_center=?

(b) F=m*a therefore a_center=20/4=5m/s^2.

Any help would be welcome in redard to what a_center is in part (a). Thanks.

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# Rope Acceleration question

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