# Rope over slope forces

1. Aug 5, 2007

### kingsgambit

1. The problem statement, all variables and given/known data

http://server7.pictiger.com/img/480530/other/forces.png [Broken]

http://server7.pictiger.com/img/480530/other/forces.png [Broken]

I would like to know the forces applied on the quadrant block as shown in the pic. Is there an equivalent force I can take for the whole quad? The block is fixed and allows the rope to slide freely. T1 and T2 (rope tensions) are different due to belt friction, but system is in static equilibrium.

I think there is an equivalent force that acts at the centre of the quad. I need this force to calculate reaction force on welded block. I'm not sure about this though.

Last edited by a moderator: May 3, 2017
2. Aug 5, 2007

The "equivalent" force is the vector T1 + T2, and it must pass through the intersection of T1 and T2.

3. Aug 5, 2007

### kingsgambit

update needs checking

http://img502.imageshack.us/my.php?image=forcesax4.png

Vertical : N*cos(A1) + W = R2
Horizontal: N*sin(a1) = R1

T1 and T2 are taken into account by N.

4. Aug 13, 2007

bumpity bump