1. The problem statement, all variables and given/known data A limp rope with a mass of 2.5 kg and a length of 1.2 m is hung, initially at rest, on a frictionless peg that has a negligible radius. The rope is hung such that 0.8m hangs off the longer end, and 0.4m off the lower end. What is the vertical velocity of the rope just as the end slides off the peg? 2. Relevant equations PE = mgh KE = 1/2mv^2 3. The attempt at a solution Because the kinematics of this system seemed incredibly complicated, I figured it best to use conservation of energy in the system. Knowing that the center of mass will fall 0.4 meters, I assumed: mgΔH = 1/2mv^2 2.5*9.81*0.4 = 1/2*2.5*v^2 v = 2.8 m/s Unfortunately, this seems to be incorrect. I assume this has something to do with the counterweight applied by the short end of the rope, but I'm not sure how to account for this.