(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

Jimmy has caught two fish in Yellow Creek. He has tied the line holding the 3.0 kg steelhead trout to the tail of the 1.5 kg carp. To show the fish to a friend, he lifts upward on the carp with a force of 60 N. What is the force of the trout on the carp?

2. Relevant equations

F_a on b = - F_b on a

Fnet = ma

3. The attempt at a solution

So i draw the free body diagrams. I draw one for the carp, and i have The applied force of 60 N upwards, and force of gravity and F_carp on trout both are downwards.

I do Fnet = 60 / 4.5 = a = 13.333

then i do Fnet for the trout = 60 - mg - F_carp on trout = 3(13.333)

I get that F_carp on trout is = -9.39

BUT i test my answer out by drawing the free body diagram for the carp. Which should have two forces on it, the force of the trout on the carp which is equal but opposite of F carp on trout, points upwards, and gravity pointing downards.

So i do Fnet carp = F_trout on carp - mg = 1.5 ( 13.333)

If i sub in the numbers, 9.39 - (1.5)(9.8), i don't end up with (1.5)(13.333)

Can someone tell me what id id wrong, thanks

EDIT: I think i know whats wrong, my fbd is wrong

**Physics Forums | Science Articles, Homework Help, Discussion**

Join Physics Forums Today!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# Homework Help: Rope tension question

**Physics Forums | Science Articles, Homework Help, Discussion**