If I take a spheroid (slightly flattened sphere) with the following equation:(adsbygoogle = window.adsbygoogle || []).push({});

x2/a2 + y2/b2 + z2/a2 - 1 = 0

and rotate it by arbitrary angles about the x-, y-, and z-axes, the new equation for the rotated spheroid is:

Ax2 + By2 + Cz2 + Dxy + Exz + Fyz + Gx + Hy + Iz + J = 0

How do I find the outline of its projection on the xy-plane?

**Physics Forums - The Fusion of Science and Community**

Join Physics Forums Today!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# Rotated Spheroid

Loading...

Similar Threads for Rotated Spheroid | Date |
---|---|

I Left translate back to I in SO(3) | Oct 3, 2017 |

Rotations in differential geometry | Jan 17, 2016 |

Ricci rotation coefficients and non-coordinate bases | Sep 21, 2015 |

Types of rotations | Sep 4, 2015 |

Deriving the Implicit Equation of a Rotated Spheroid | Jul 31, 2005 |

**Physics Forums - The Fusion of Science and Community**