# Rotating rod

1. Aug 6, 2007

### Stas

anybody know link where i can see how to calculate the power of the gravitational radiation emitted from a rotating rod?

2. Aug 6, 2007

### pervect

Staff Emeritus
MTW's "Gravitation" gives a formula on pg 980.

In geometric units, the formula is:

$$L_{GW} = \frac{2}{45} M^2 l^4 \omega^6$$

where M is the mass of the bar
l is the length of the bar
$\omega$ is the angular frequency of rotation of the bar, $\frac{2 \pi}{T}$, where T is the period of rotation of the bar.

Converting this to standard units we get

$$L_{GW} =\frac{2}{45} \frac{G}{c^5} M^2 l^4 \omega^6$$

the added constants are c, the speed of light, and G, the gravitational constant.

Last edited: Aug 6, 2007