- #1
afromanam
- 16
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This problem is from Vectorial Mechanics for engineers:Statics of Beer and Johnston
it's about friction
it says: suppose that a cylinder of weight W and radius R has the same coefficient of static friction in A and B. Determine the magnitude of the maximum momentus M that can be applied to the cylinder so it doesn't rotate.
The cylinder is in a corner and it touches only a wall (A) and the floor (B) (this is in case the attachment does not display properly)
I think i figured out what happens when the cylinder doesn't touch point (A) or when the coefficient of static friction (U*) in A is zero, but I really have no clue of what happens when we consider point A.
my guess is that when U*A is zero the answer is:
M = WRU*B
the complete answer is:
M = WRU*(1+U*)/(1+(U*^2))
i'd really appreciate if you could point me in the right direction.
thanks in advance. :shy: :shy:
it's about friction
it says: suppose that a cylinder of weight W and radius R has the same coefficient of static friction in A and B. Determine the magnitude of the maximum momentus M that can be applied to the cylinder so it doesn't rotate.
The cylinder is in a corner and it touches only a wall (A) and the floor (B) (this is in case the attachment does not display properly)
I think i figured out what happens when the cylinder doesn't touch point (A) or when the coefficient of static friction (U*) in A is zero, but I really have no clue of what happens when we consider point A.
my guess is that when U*A is zero the answer is:
M = WRU*B
the complete answer is:
M = WRU*(1+U*)/(1+(U*^2))
i'd really appreciate if you could point me in the right direction.
thanks in advance. :shy: :shy: