A bicycle has wheels of 1.2m diameter. the bicyclist accelerates from rest with constant acceleration to 24km/h in 14.0s. What is the angular acceleration of the wheels? If the bicycle is going forwards relative to the ground with a speed of 24km/h, then, all points on the tread are moving around the wheel with a speed (s) of 24km/h relative to the axel. s = 24km/h = 6.7m/s (I know the significant figures rules but I dont know where to round) r = 1.2m/2 = 0.6m w=s/r w=6.7/0.6 = 11.2 rad/s ( is my rounding correct here?) a=v^2/r=(6.7)^2/0.6= 74.8m/s^2 Is the reasoning correct? Thank you for your help.