- #1
cristina
- 53
- 0
The radius of a park merry-go-round is 2.2m. To start it rotating, you wrap a rope around it and pull with a force of 260N for 12s. During this time, the merry-go-round makes one complete rotation. a) Find the angular acceleration of the merry-go-round. b) What torque is exerted by the rope on the merry-go-round? c) What is the moment of inertia of the merry-go-round?
A)
The angular acceleration is alpha = Torque/I
I did conceder the merry-go-round as a solid cylinder so I =1/2(MR^2)
Torque = Fr
Acceleration = (260N * 2.2m)/(1/2(MR^2))
I don’t know how to get rid of the M?
B)
Torque = Fr = (260N * 2.2m) = 572 Nm
C) The moment of inertia of the merry-go-round is I =1/2(MR^2)
Can I get the M in the torque from F = ma (after I know the acceleration from a) )?
Thank you
A)
The angular acceleration is alpha = Torque/I
I did conceder the merry-go-round as a solid cylinder so I =1/2(MR^2)
Torque = Fr
Acceleration = (260N * 2.2m)/(1/2(MR^2))
I don’t know how to get rid of the M?
B)
Torque = Fr = (260N * 2.2m) = 572 Nm
C) The moment of inertia of the merry-go-round is I =1/2(MR^2)
Can I get the M in the torque from F = ma (after I know the acceleration from a) )?
Thank you