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Rotation in the Kerr metric?

  1. Jan 2, 2015 #1
    I understand the Kerr metric has an off-diagonal term between the rotation and the time degrees-of-freedom? That a test mass falling straight down toward a large rotating mass from infinity will begin to pick up angular momentum? Is that what’s called “frame dragging”? Did the Gravity Probe B verify that effect?

    Finally my main question: what is the large mass rotating with respect to? Before someone says “the distant stars”, remember that the Kerr metric is a MODEL of an otherwise empty universe. I don’t think there are any “distant stars” in the MODEL. I am not that familiar with this metric yet, but I assume that like the Schwarzschild it asymptotically goes to Minkowski at infinity?
     
  2. jcsd
  3. Jan 2, 2015 #2

    Dale

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    Rotation is non inertial. It is not relative like velocity. You don't need a "with respect to" for rotation.
     
  4. Jan 2, 2015 #3

    PeterDonis

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    2016 Award

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    "Degrees of freedom" is not really the right term, but yes, there is an off-diagonal ##dt d\phi## term in the Kerr metric. More precisely, there is one off-diagonal term in the Kerr metric in Boyer-Lindquist coordinates (which are basically the analogue in Kerr spacetime of Schwarzschild coordinates in Schwarzschild spacetime); in other charts there may be more than one. A coordinate-independent way of putting it is to say that the "time translation" Killing vector field in Kerr spacetime is not orthogonal to the spacelike hypersurfaces in which the orbits of the "rotation" Killing vector field lie.

    Strictly speaking, the Kerr metric does not describe a large rotating "mass" such as a planet or star. It describes a rotating black hole. It is believed that the Kerr metric (or at least a portion of it) also describes spacetime, at least approximately, around a rotating mass like a planet or star, but this has not been proven.

    No, it will begin to pick up angular velocity. One of the counterintuitive things about Kerr spacetime is that nonzero angular velocity does not always mean nonzero angular momentum. A test object that starts with zero angular momentum at infinity and falls into a Kerr black hole will have zero angular momentum throughout its fall--angular momentum is a constant of the motion for freely falling objects in Kerr spacetime, just as it is in Schwarzschild spacetime. But because of the non-orthogonality described above, this zero angular momentum object will pick up angular velocity as it falls.

    It's one manifestation of frame dragging, yes. There are others as well.

    It verified a different manifestation of frame dragging, its effect on a gyroscope in a free-fall nearly circular orbit about a rotating mass. (Note, again, that the presence of frame dragging in the spacetime around the Earth does not prove that the Kerr metric exactly describes that spacetime. It only proves that there is one particular term in the metric around the Earth that corresponds to what you would get if you did a weak-field approximation based on the Kerr metric--more precisely, based on expressing the Kerr metric as the Schwarzschild metric plus small perturbations.)
     
  5. Jan 2, 2015 #4

    PeterDonis

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    Yes.
     
  6. Jan 3, 2015 #5

    WannabeNewton

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    "Frame dragging" is a very general term when applied to general stationary axisymmetric space-times that takes on varied meanings based on the context. There are three rather canonical examples of frame dragging: a test particle is dropped from spatial infinity with zero angular momentum and free falls toward the central rotating mass and in doing so, it gains an angular velocity (not angular momentum, due to conservation of said quantity) around the central mass because the space-time itself rotates relative to spatial infinity; a gyroscope at rest relative to spatial infinity whose axis is fixed to the distant stars will start precessing relative to local Fermi-Walker transported gyroscope axes; a gyroscope in orbit around the central mass with the zero angular momentum parameters whose axis is fixed to the local space-time symmetries will precess relative to comoving Fermi-Walker transported gyroscope axes. The second effect is called the Lense-Thirring precession and the latter effect is a combination of Lense-Thirring, geodetic, and Thomas precessions.

    It verified Lense-Thirring and geodetic precessions to different accuracy.

    It rotates with respect to the asymptotic Minkowskian (flat space-time) Lorentz frame at spatial infinity.
     
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