1. The problem statement, all variables and given/known data A 2.05 kg, 33.64 cm diameter turntable rotates at 365 rpm on frictionless bearings. Two 280 g blocks fall from above, hit the turntable simultaneously at opposite ends of a diagonal, and stick. What is the turntable's angular velocity, in rpm, just after this event? 2. Relevant equations I= m(r^2)/2 Ki=I(w^2)/2 3. The attempt at a solution I changed the 365 rpm to 38.22 rad/s Then i found that the Ki=mt(r^2)(wi^2)/2 Then i found that the Kf=(mt+mb1+mb2)(r^2)(wi^2)/2) Then i solved for wf and got the equation mt*wi^2/(the mass of the turntable and blocks). Then the square root of that and got 33.87 rad/s Then turned 33.87 rad/s to rpm and got 323.46.....Did i use the wrong I maybe? I used the I from above. and combined it with the Kinetic energy.