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Rotation of a viewpoint

  1. Jul 14, 2017 #1
    1. The problem statement, all variables and given/known data
    I am working in Matlab, and have a 3D plot that I made:
    [​IMG]
    mkx2mt.png
    [​IMG]x is parallel to axis labeled "lateral direction (m)"
    y is parallel to axis labeled "long. dir. (m)"
    z is normal to these (right hand coordinate sytem)

    The original view was looking parallel with +y. To get the current view, I rotated our viewpoint about the x axis -15 degrees, then rotated about the ORIGINAL z axis 10 degrees.

    How do I calculate the angle that the x axis now forms on the page?

    For comparison, I used image editing software to measure the angle of the axis. It is a rectangle 12 high, 322 wide, so the angle is -2.134 deg.

    2. Relevant equations


    3. The attempt at a solution
    I attempted to do rotation matrices. I did:
    phi = -15deg
    theta = 10deg

    A =
    [cos(theta) sin(theta) 0;
    -sin(theta) cos(theta) 0;
    0 0 1]

    B =
    [1 0 0;
    0 cos(phi) -sin(phi);
    0 sin(phi) cos(phi)]

    B*A =
    [ cos(theta), cos(phi)*sin(theta), -sin(phi)*sin(theta);
    [ -sin(theta), cos(phi)*cos(theta), -cos(theta)*sin(phi);
    [ 0, sin(phi), cos(phi)]

    And do get the angle that the original x axis forms with our new viewpoint, I do

    r =
    [1;
    0;
    0]

    then do:
    B*A*r

    and I get:
    [cos(theta);
    -sin(theta);
    0]

    Which does not give me a correct result. Not only that, there is no way that a rotation in two different axes does not depend on both theta and phi.
     
    Last edited: Jul 14, 2017
  2. jcsd
  3. Jul 14, 2017 #2
    I made a mental faux pas. The reason for the discrepancy is that the axes in MATLAB are not equal by default. Once I set the axes to be equal, my calculated angle matches the measured axis angle.
     
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