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Rotation operator

  • Thread starter zDrajCa
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  • #1
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Poster has been reminded to use the Homework Help Template when starting threads in the schoolwork forums
Hi, i'm working on the interaction between a two level atom (|g>, |e>)
In my exercise we have to use the rotation operator :

R(t)=exp[i(σz+1)ωt/2]

with σz the pauli matrix which is in the {|g>,|e>} basis :
(1 0)
(0 -1)

If i want to represent my rotation operator in the {|g>,|e>} basis. Then i can do:
σz +1 = (1 is the identity matrix)
( 2 0)
( 0 0)

Do my operator is :
(exp(iwt) 0 )
( 0 exp(0) )

Thanks for your answers.
 

Answers and Replies

  • #2
scottdave
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I'm not familiar with taking exponential of a matrix. But if you had exp(0) in the lower right position, would it also be exp(0) in the upper right and lower left?
 
  • #3
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i have read that if a matrix was diagonal (my case right) ,then the exponential of the matrix is the exponential of his diagonal term
 
  • #4
TeethWhitener
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