- #1

timtng

- 25

- 0

This is what I came up with, but don't know if I did it correctly:

For frictional force I got μMg

-net torque = I(alpha), alpha = -μMg/.5MR = -2μg/R

ω = ω0 +alpha(t) >> 0 = ω-(2μg/R)t

I got t = (ωR)/(2μg) >>Is this the correct answer?

Thanks