This is another attempt at an earlier question that maybe wasn't done in a readable format.(adsbygoogle = window.adsbygoogle || []).push({});

This was in Strang page 230. Could someone derive this?

[tex]

if K = \left[\begin{array} {cc} 0&-1\\1&0\end{array}\right]

then \quad e^{Kt} = \left[\begin{array} {cc} cos t & -sin t\\sin t & cos t\end{array}\right]

[/tex]

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# Homework Help: Rotation try again.

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