- #1
BlasterV
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one block has a mass M = 500 g, the other has mass m = 460 g, and the pulley, which is mounted in horizontal frictionless bearings, has a radius of 5.00 cm. When released from rest, the heavier block falls 85.5 cm in 2.47 s (without the cord slipping on the pulley).
First I did conversions:
M = .5kg, m = .46 kg, r = .05 m
fall = .855m in 2.47 s
I am unable to do part b and c right, so I am unable to go further.
Here is my work:
.855m = 1/2 a (2.47^2) a = .28 m/s^2
however, It asks for 2 tensions. I never learned how to separate them like that, especially with a pulley. I did:
9.8 m/s^2 * .5kg = 4.9 N
9.8 m/s^2 * .46kg = 4.508 N
Tension of Cord = 4.9N + 4.508N. Obviously this isn't right, where do I go from here, or did I miss something?
(a) What is the magnitude of the block's acceleration?
.28 m/s2
(b) What is the tension in the part of the cord that supports the heavier block?
N
(c) What is the tension in the part of the cord that supports the lighter block?
N
(d) What is the magnitude of the pulley's angular acceleration?
rad/s2
(e) What is its rotational inertia?
kg · m2
First I did conversions:
M = .5kg, m = .46 kg, r = .05 m
fall = .855m in 2.47 s
I am unable to do part b and c right, so I am unable to go further.
Here is my work:
.855m = 1/2 a (2.47^2) a = .28 m/s^2
however, It asks for 2 tensions. I never learned how to separate them like that, especially with a pulley. I did:
9.8 m/s^2 * .5kg = 4.9 N
9.8 m/s^2 * .46kg = 4.508 N
Tension of Cord = 4.9N + 4.508N. Obviously this isn't right, where do I go from here, or did I miss something?
(a) What is the magnitude of the block's acceleration?
.28 m/s2
(b) What is the tension in the part of the cord that supports the heavier block?
N
(c) What is the tension in the part of the cord that supports the lighter block?
N
(d) What is the magnitude of the pulley's angular acceleration?
rad/s2
(e) What is its rotational inertia?
kg · m2
Last edited: