1. The problem statement, all variables and given/known data A 2kg , 0.2 m diameter turntable rotates at 100 rpm on frictionless bearings. Two 0.5 kg block fall from above, hit the turntable simultaneously at opposite ends of the diameter, and stick. What is the turntable's angular velocity (in rpm) just after? 2. Relevant equations L= I x ω Li = Lf Moment of inertia for disk I = (1/2) MR2 Moment of inertia for point mass = MR2 3. The attempt at a solution I converted 100 rpm to rotations per sec by dividing by 60 which gives me (5/3). I thought about the problem and came up with the idea of conservation of angular momentum so Li = Lf. Li = I x ω= (1/2)MR2 x ω. I am confused. The answer has to be in rpm but ω has the SI units of rad/s. Does unit consistency play a role here since I have ω on both sides of the equation. I thought that before doing it with numbers, using only variables to make sure I understand what I am doing. Lf= Isys x ωf So my question here is, does this reflect what is happening when the blocks stick to the plate? I reasoned that the blocks added moment of inertia to the system. I continued and Isys = [((1/2)MR2 x ω) + ( MBlock R2 + MBlock R2)]. Is that correct? Then I set them equal with Li =Lf and solved for angular velocity. I continued and plugged in the given values and got a completely different answers. I feel like my approach is missing out on something. The problem gave the answer which is 5.24 rad/sec or 50rpm.