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[Rotational dynamics] cube sliding on a dish
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[QUOTE="Nathanael, post: 5453553, member: 509990"] I think your book really messed up... The point of the vertical wall around the dish is to provide the centripetal force. It's still possible for the frictional force to have some centripetal component, and in this sense the problem is a bit ambiguous, but, I think the problem creator intended the entire centripetal force to be provided by the wall, so that friction is entirely tangential. (Notice you implicitly assumed this, because only the tangential component of friction will do work.) I solved the problem by different means (I considered the kinematics instead of work) and I arrived at the same answer as you, 0.092 Newtons. As for your second equation, it does not make sense... Equal and opposite forces do not imply conservation of kinetic energy. (You never used this equation in your solution though, so I still agree with your method.) [/QUOTE]
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[Rotational dynamics] cube sliding on a dish
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